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210y^2-319y+121=0
a = 210; b = -319; c = +121;
Δ = b2-4ac
Δ = -3192-4·210·121
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-319)-11}{2*210}=\frac{308}{420} =11/15 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-319)+11}{2*210}=\frac{330}{420} =11/14 $
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